3.318 \(\int \frac {\sec ^4(e+f x)}{\sqrt [3]{b \sin (e+f x)}} \, dx\)

Optimal. Leaf size=58 \[ \frac {3 \sqrt {\cos ^2(e+f x)} \sec (e+f x) (b \sin (e+f x))^{2/3} \, _2F_1\left (\frac {1}{3},\frac {5}{2};\frac {4}{3};\sin ^2(e+f x)\right )}{2 b f} \]

[Out]

3/2*hypergeom([1/3, 5/2],[4/3],sin(f*x+e)^2)*sec(f*x+e)*(b*sin(f*x+e))^(2/3)*(cos(f*x+e)^2)^(1/2)/b/f

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Rubi [A]  time = 0.04, antiderivative size = 58, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.048, Rules used = {2577} \[ \frac {3 \sqrt {\cos ^2(e+f x)} \sec (e+f x) (b \sin (e+f x))^{2/3} \, _2F_1\left (\frac {1}{3},\frac {5}{2};\frac {4}{3};\sin ^2(e+f x)\right )}{2 b f} \]

Antiderivative was successfully verified.

[In]

Int[Sec[e + f*x]^4/(b*Sin[e + f*x])^(1/3),x]

[Out]

(3*Sqrt[Cos[e + f*x]^2]*Hypergeometric2F1[1/3, 5/2, 4/3, Sin[e + f*x]^2]*Sec[e + f*x]*(b*Sin[e + f*x])^(2/3))/
(2*b*f)

Rule 2577

Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[(b^(2*IntPart
[(n - 1)/2] + 1)*(b*Cos[e + f*x])^(2*FracPart[(n - 1)/2])*(a*Sin[e + f*x])^(m + 1)*Hypergeometric2F1[(1 + m)/2
, (1 - n)/2, (3 + m)/2, Sin[e + f*x]^2])/(a*f*(m + 1)*(Cos[e + f*x]^2)^FracPart[(n - 1)/2]), x] /; FreeQ[{a, b
, e, f, m, n}, x]

Rubi steps

\begin {align*} \int \frac {\sec ^4(e+f x)}{\sqrt [3]{b \sin (e+f x)}} \, dx &=\frac {3 \sqrt {\cos ^2(e+f x)} \, _2F_1\left (\frac {1}{3},\frac {5}{2};\frac {4}{3};\sin ^2(e+f x)\right ) \sec (e+f x) (b \sin (e+f x))^{2/3}}{2 b f}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 55, normalized size = 0.95 \[ \frac {3 \sqrt {\cos ^2(e+f x)} \tan (e+f x) \, _2F_1\left (\frac {1}{3},\frac {5}{2};\frac {4}{3};\sin ^2(e+f x)\right )}{2 f \sqrt [3]{b \sin (e+f x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sec[e + f*x]^4/(b*Sin[e + f*x])^(1/3),x]

[Out]

(3*Sqrt[Cos[e + f*x]^2]*Hypergeometric2F1[1/3, 5/2, 4/3, Sin[e + f*x]^2]*Tan[e + f*x])/(2*f*(b*Sin[e + f*x])^(
1/3))

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fricas [F]  time = 0.52, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\left (b \sin \left (f x + e\right )\right )^{\frac {2}{3}} \sec \left (f x + e\right )^{4}}{b \sin \left (f x + e\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(f*x+e)^4/(b*sin(f*x+e))^(1/3),x, algorithm="fricas")

[Out]

integral((b*sin(f*x + e))^(2/3)*sec(f*x + e)^4/(b*sin(f*x + e)), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec \left (f x + e\right )^{4}}{\left (b \sin \left (f x + e\right )\right )^{\frac {1}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(f*x+e)^4/(b*sin(f*x+e))^(1/3),x, algorithm="giac")

[Out]

integrate(sec(f*x + e)^4/(b*sin(f*x + e))^(1/3), x)

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maple [F]  time = 0.10, size = 0, normalized size = 0.00 \[ \int \frac {\sec ^{4}\left (f x +e \right )}{\left (b \sin \left (f x +e \right )\right )^{\frac {1}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(sec(f*x+e)^4/(b*sin(f*x+e))^(1/3),x)

[Out]

int(sec(f*x+e)^4/(b*sin(f*x+e))^(1/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec \left (f x + e\right )^{4}}{\left (b \sin \left (f x + e\right )\right )^{\frac {1}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(f*x+e)^4/(b*sin(f*x+e))^(1/3),x, algorithm="maxima")

[Out]

integrate(sec(f*x + e)^4/(b*sin(f*x + e))^(1/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {1}{{\cos \left (e+f\,x\right )}^4\,{\left (b\,\sin \left (e+f\,x\right )\right )}^{1/3}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(cos(e + f*x)^4*(b*sin(e + f*x))^(1/3)),x)

[Out]

int(1/(cos(e + f*x)^4*(b*sin(e + f*x))^(1/3)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec ^{4}{\left (e + f x \right )}}{\sqrt [3]{b \sin {\left (e + f x \right )}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(sec(f*x+e)**4/(b*sin(f*x+e))**(1/3),x)

[Out]

Integral(sec(e + f*x)**4/(b*sin(e + f*x))**(1/3), x)

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